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Home/ Questions/Q 860841
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:52:49+00:00 2026-05-15T08:52:49+00:00

The first solution is: std::vector<int> *vec = new std::vector<int>; assert(vec != NULL); // …

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The first solution is:

std::vector<int> *vec = new std::vector<int>;
assert(vec != NULL);
// ...
delete vec;

An alternative is:

std::vector<int> v;
//...
vec.clear();
vec.swap(std::vector<int>(vec));

The second solution’s a bit of a trick — what’s the "right" way to do it?

Update:

I’m aware that the destructor will be called once it’s off the stack, I was curious about other methods.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T08:52:49+00:00Added an answer on May 15, 2026 at 8:52 am

    The simplest and most reliable way to deallocate a vector is to declare it on the stack and simply do nothing.

    void Foo() {
      std::vector<int> v;
      ...
    }
    

    C++ guarantees that the destructor of v will be called when the method executes. The destructor of std::vector will ensure any memory it allocated is freed. As long as the T type of the vector<T> has proper C++ deallocation semantics all will be well.

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