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Home/ Questions/Q 6626371
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:53:05+00:00 2026-05-25T21:53:05+00:00

the following code can be compiled correctly on both VC or gcc: char *str

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the following code can be compiled correctly on both VC or gcc:

char *str = "I am a const!";
str[2] = 'n';

however, obviously there is a run-time-error. Since “I am a const!” is a const char*, why the compiler doesn’t give an error or even a warning ??


Besides, if I define char a[] = "I am const!", all the elements in a can be modified, why this time the string literals become nonconst ?

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:53:06+00:00Added an answer on May 25, 2026 at 9:53 pm

    As far as C is concerned, that string literal is not const, it’s a char[14] which you assign to a char*, which is perfectly fine.

    However, C does say that changing a string literal is undefined behavior.

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