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Home/ Questions/Q 3275910
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:11:50+00:00 2026-05-17T19:11:50+00:00

The following code compiled with MSVC9.0 runs and outputs Destructor four times, which is

  • 0

The following code compiled with MSVC9.0 runs and outputs Destructor four times, which is logical.

#include <iostream>
class SomeClass
{
public:
   void CommitSuicide()
   {
      delete this;
   }
   void Reincarnate()
   {
      this->~SomeClass();
      new (this) SomeClass;
   }
   ~SomeClass()
   {
      std::cout  << "Destructor\n";
   }
};

int main()
{
   SomeClass* p = new SomeClass;
   p->CommitSuicide();
   p =  new SomeClass;
   p->Reincarnate();
   p->~SomeClass(); //line 5
   p->CommitSuicide();
}

I think the first 4 lines of code in main do not result in undefined behavior (although not entirely sure about the delete this; thing). I would like to have a confirmation or < placeholder for confirmation’s antonym > of that. But I have serious doubts about lines 5 and 6. It is allowed to explicitly call the destructor, isn’t it? But is the lifetime of the object considered to have finished after that? That is, is invocation of another member after the explicit call of the destructor allowed (defined)?

To summarize, which parts of the above code (if any) result in undefined behavior (technically speaking)?

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:11:51+00:00Added an answer on May 17, 2026 at 7:11 pm

    p->~SomeClass(); //line 5

    p->CommitSuicide(); //line 6

    Line (6) definitely invokes Undefined Behaviour.

    That is, is invocation of another member after the explicit call of the destructor allowed (defined)?

    No! Your assumption is correct.

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