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Home/ Questions/Q 7796089
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:15:51+00:00 2026-06-01T23:15:51+00:00

The following code compiles without any warning or error on G++ (GCC) 4.1.2. Is

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The following code compiles without any warning or error on G++ (GCC) 4.1.2.

Is there a reason for not issuing an error/warning?

Is there a flag that can cause it to issue a warning or error?

#include <iostream>

using namespace std;

void func(string &s)
{
    unsigned long u = 123;
   s = u;
}

int main()
{
   string s;

   func (s);

   return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-06-01T23:15:53+00:00Added an answer on June 1, 2026 at 11:15 pm

    The reason there’s no warning or error is because this is valid C++. std::string overloads the assignment operator (operator=) to take a char. long can be implicitly converted to a char, hence the code makes sense.

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