Question

The following code does not produce an exception but instead passes the value 4 to tst. Can anyone explain the reason behind this?

 public enum testing  {      a = 1,     b = 2,     c = 3  }  testing tst = (testing)(4); 

Answer 1

In C#, unlike Java, enums are not checked. You can have any value of the underlying type. This is why it’s pretty important to check your input.

if(!Enum.IsDefined(typeof(MyEnum), value))      throw new ArgumentOutOfRangeException();