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Home/ Questions/Q 272521
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T00:19:32+00:00 2026-05-12T00:19:32+00:00

The following code does not run as rootNode is null when retrieved by name

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The following code does not run as rootNode is null when retrieved by name “RootNode”

 treeView1.Nodes.Add(new TreeNode("RootNode"));

 ...
 //get the rootNode by its name
 TreeView1 rootNode = treeView1.Nodes["RootNode"]

 //rootNode is null so following line throws an error
 rootNode.Nodes.Add(new TreeNode("ChildNode"));

What am I missing here? How can I get a particular node by it’s name??

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  1. Editorial Team
    Editorial Team
    2026-05-12T00:19:32+00:00Added an answer on May 12, 2026 at 12:19 am

    The TreeNode constructor does not accept a key / name parameter. The indexer is based on the tree node’s name, not its text. Therefore you either need to set the tree node’s name or use a different add method like this:

    treeView1.Nodes.Add("RootNode", "Root Node");
    
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