Question

The following code does two things:

1. Checks to see if the item has the key “checkins”
2. Gets the checkins value if it has the key

I really don’t like making two API calls for this. Its really slowed my code down but I’m forced to because if I make the API call for checkins and the key doesn’t exist, then my code blows up. There must be a better way to do this.

if graph.get_object(self.place_id).has_key?("checkins") 
  checkins =  graph.get_object(self.place_id)["checkins"] - self.checkins
else 
  checkins = self.checkins
end

Answer 1

graph_checkins = graph.get_object(self.place_id)["checkins"]
checkins = if graph_checkins
             graph_checkins - self.checkins
           else
             self.checkins
           end