Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 840027
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T05:33:33+00:00 2026-05-15T05:33:33+00:00

The following code fails to compile: class MyClass<T> : where T : MyClass <T>{}

  • 0

The following code fails to compile:

class MyClass<T> :  where T : MyClass <T>{}

Is there any way to solve this?
I have used the following workaround but I was wondering if there is a better way

class MyClass <T> : IMyClass where T : IMyClass {}
interface IMyClass {}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T05:33:35+00:00Added an answer on May 15, 2026 at 5:33 am

    You need to put a colon after the class name only if you want to derive the class from a base class or implement an interface:

    class MyClass<T> where T : MyClass<T>
    //              ↑
    //              no ':' here
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

The following code fails in 'Evaluate' with: This expression was expected to have type
The following code fails to compile on g++ 4.6.1: template<class Base> struct GetBase {
The following code compiles perfectly with Eclipse, but fails to compile with javac: public
Please explain why the following code snippet fails to compile: public class ScjpTest{ static
I m trying to compile this code and linking fails with the following error:
So, I have the following code which fails to compile on gcc 4.2.1 on
I have the following code and it fails to compile template < typename T
The following code does not compile ... any idea why? Is this illegal C++?
The following code compiles in Visual Studio 2010 but fails to compile in the
The following code fails to compile #include <iostream> #include <cmath> #include <complex> using namespace

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.