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Home/ Questions/Q 4558202
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T17:36:58+00:00 2026-05-21T17:36:58+00:00

The following code gives me the following: $getexpenses = SELECT sum(expense_amount) FROM projects_expense WHERE

  • 0

The following code gives me the following:

$getexpenses = "SELECT sum(expense_amount) FROM projects_expense WHERE project_id=$project_id";     
    $showexpenses = @mysqli_query ($dbc, $getexpenses); // Run the query.

    echo ' . $showexpenses . ';

Gives me a result of

' . $showexpenses . '

instead of the actual sum…

I’m sure it’s something simple I’m missing… thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T17:36:58+00:00Added an answer on May 21, 2026 at 5:36 pm

    I added a call to mysqli_fetch_assoc($showexpenses)to make it fully functional.
    I also sanitized $project_id to avoid injections and used an alias to make the sum accessible through an associative array.

    $getexpenses = "SELECT SUM(`expense_amount`) as `sum_amount` FROM `projects_expense` WHERE `project_id`= ".intval($project_id);     
    $showexpenses = mysqli_query ($dbc, $getexpenses);
    $sums = mysqli_fetch_assoc($showexpenses);
    $sum = $sums['sum_amount'];
    
    echo $sum;
    

    We could also have used mysqli_fetch_row like this:

    $getexpenses = "SELECT SUM(`expense_amount`) FROM `projects_expense` WHERE `project_id`= ".intval($project_id);     
    $showexpenses = mysqli_query ($dbc, $getexpenses);
    $sums = mysqli_fetch_row($showexpenses);
    $sum = $sums[0];
    
    echo $sum;
    

    The alias is not needed anymore since we know the first column (0) is a match.

    NB: you probably also need to GROUP BY project_id if you want to use SUM()

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