The following code gives me the output as ‘d’:
void main()
{
short int a=5;
printf("%d"+1,a);
getch();
}
How does printf() actually work?
The following code gives me the output as ‘d’: void main() { short int
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The following code gives me the output as ‘d’:
void main()
{
short int a=5;
printf("%d"+1,a);
getch();
}
How does printf() actually work?
printfdoes not “see” the format specifier because you are passing a pointer to"%d"plus one. This is equivalent to passing"d"by itself:will print
dand ignorea. This is not specific toprintf, pointer arithmetic works like that with allcharpointers, including pointers obtained from string literals (i.e. double-quoted sequences of characters).