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Home/ Questions/Q 6591525
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:26:04+00:00 2026-05-25T17:26:04+00:00

The following code has me confused int a=2,b=5,c; c=a+++b; printf(%d,%d,%d,a,b,c); I expected the output

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The following code has me confused

int a=2,b=5,c;
c=a+++b;
printf("%d,%d,%d",a,b,c);

I expected the output to be 3,5,8, mainly because a++ means 2 +1 which equals 3, and 3 + 5 equals 8, so I expected 3,5,8. It turns out that the result is 3,5,7. Can someone explain why this is the case?

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:26:04+00:00Added an answer on May 25, 2026 at 5:26 pm

    It’s parsed as c = a++ + b, and a++ means post-increment, i.e. increment after taking the value of a to compute a + b == 2 + 5.

    Please, never write code like this.

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