The following code is not working correctly. I’m getting a segfault when I run the program. I ran my program through gdb and found out that the error is occuring in the fillArrays(int**,int) function.
GDB is displaying the following parameters for fillArrays(int**,int):
fillArrays (arrays=0x0,numArrays=3)
Here is the source code to my program
#include <stdlib.h> /* malloc and free */
#define MULTIPLIER 1
#define SMALL 10
#define BIG 20
void allocateSmallArrays(int **arrays,int numArrays) {
int index,freeIndex;
int outerIndex,innerIndex;
arrays = malloc(numArrays*sizeof(int*));
if(arrays == NULL) {
printf("out of memory\n");
exit(1);
}
for(index = 0;index < numArrays;index++) {
arrays[index] = malloc(SMALL*sizeof(int));
if(arrays[index] == NULL) {
printf("out of memory\n");
exit(1);
}
}
}
void fillArrays(int **arrays,int numArrays) {
int outerIndex,innerIndex;
for(outerIndex = 0;outerIndex < numArrays;outerIndex++) {
for(innerIndex = 0;innerIndex < SMALL;innerIndex++)
arrays[outerIndex][innerIndex] = 0;
}
}
void deallocateSmallArrays(int **arrays,int numArrays) {
int index;
for(index = 0;index < numArrays;index++)
free(arrays[index]);
free(arrays);
}
int main(void) {
int numArrays = (3 * MULTIPLIER);
int **arrays = 0;
allocateSmallArrays(arrays,numArrays);
fillArrays(arrays,numArrays);
deallocateSmallArrays(arrays,numArrays);
arrays = 0;
return 0;
}
I was under the assumption that since arrays was allocated in allocateSmallArrays, that passing it through fillArrays would 0 out the allocated arrays and then deallocate in the last function. How do I go about accomplishing this?
The problem is that
allocateSmallArrayschanges its own copy of thearrayspointer. So the result of themallocis lost and after the function is done, in the callerarraysis still 0. You could:Pass a triple pointer
int ***arraysand do to*arrayseverything you’re doing toarraysReturn the pointer instead of void
A C FAQ deals with this very subject.