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Home/ Questions/Q 9096247
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T23:47:53+00:00 2026-06-16T23:47:53+00:00

The following code is not working. Whatever I input just returns an error, and

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The following code is not working. Whatever I input just returns an error, and then goes back to Retry.

@echo off

:maths
set /p Mathsa="first number? "
echo your first number is %Mathsa%

:retry

set /p Mathso="operator?(+-*/) "
if "%Mathso%" ==* GOTO run
if "%Mathso%" ==/ GOTO run
if "%Mathso%" ==+ GOTO run
if "%Mathso%" ==- GOTO run
echo Error, wrong operator. & goto retry

:run
set /p Mathsb="Second Number? "
set /a Mathsans=%Mathsa%%Mathsp%%Mathsb%
echo %Mathsans%
pause

I have absolutely no idea why it’s doing this. It’s for a school project and any help you can give would be appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T23:47:54+00:00Added an answer on June 16, 2026 at 11:47 pm

    It’s the quotes around your Mathso variable. Change them all to use quotes around both sides of the equality, such as with:

    if "%Mathso%" == "+" GOTO run
    

    and they should work better.

    The reason for this is that cmd is not quite the same as UNIXy shells. The quotes are preserved on the left hand of the equality so that what you end up with is:

    if "+" == + then ...
    

    and "+" is not equal to +.

    By putting quotes on both sides, it becomes:

    if "+" == "+" then ...
    

    which is true.


    And, as Aacini points out in the comment, your calculation set uses the wrong variable for the operator. You should change:

    set /a Mathsans=%Mathsa%%Mathsp%%Mathsb%
    

    into:

    set /a Mathsans=%Mathsa%%Mathso%%Mathsb%
                                  ^
                                  |
                                  see here
    
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