Question

The following code is producing a list with the non-expired rows on top, then the ones with unknown expiry date and at the end the already expired (all of them in ascending order). The problem is that I want the last block of already expired rows to be in descending order so it displays the rows that expired more recently on top of that block without altering the order of the other top blocks.

Basically, I am trying to find a way to incorporate two “ORDER BY” clauses within the same recordset…

Any ideas? Thanks

SELECT *
  FROM prueba 
 WHERE UPPER(CONCAT(Company,Deal,keywords,Type,Expiry,Name)) LIKE UPPER(%s) 
ORDER BY (CASE 
            WHEN prueba.Expiry = 'UNKNOWN' THEN 1 
            WHEN prueba.Expiry < CURRENT_DATE THEN 2 
          END)
       , prueba.Expiry ASC

Answer 1

Try this

DEMO FIDDLE

SELECT * FROM t
order by case 
      when expiry = 'Unknown' Then 1 
      WHEN expiry >= CURRENT_DATE THEN 0 
      ELSE 2 END,
CASE WHEN expiry >= CURRENT_DATE THEN expiry END,
CASE WHEN expiry < CURRENT_DATE THEN expiry END desc