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Home/ Questions/Q 9152847
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:09:16+00:00 2026-06-17T12:09:16+00:00

The following code is supposed to print inside init() — inside start() — inside

  • 0

The following code is supposed to print

inside init()— inside start()— inside paint().

But it prints the last part inside paint() TWICE! Why is that?

public class SampleApplet extends Applet {

String msg;

@Override
public void init(){
    setBackground(Color.BLACK);
    setForeground(Color.yellow);
    msg = "Inside init()-- ";
  }

@Override 
public void start(){
    msg += "Inside start()-- ";
  }

@Override 
public void paint(Graphics g){
    msg += "Inside paint().";
    g.drawString(msg, 10, 30);
  }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:09:17+00:00Added an answer on June 17, 2026 at 12:09 pm

    Quoted from: Paint():

    the paint() method will be called as many times as necessary. If you
    put another window over your GUI then the paint() method will be
    called. If you then minimize that window and make your GUI visible
    again then the paint() method will be called again. And so on.

    So if you have something that is a problem if the paint() method is
    called more than once, you have done it wrong. Don’t do it that way.
    The paint() method should only redraw its target from existing data,
    it should never have to do calculations to figure out what to paint.

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