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Home/ Questions/Q 4343300
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T11:43:58+00:00 2026-05-21T11:43:58+00:00

The following code is used to get Youtube video ids in order to get

  • 0

The following code is used to get Youtube video ids in order to get a thumbnail image.

What is the reasoning behind the first regular expression and what is it doing exactly? It appears to be returning at least two results. Also, could the two be combined?

else if(url.match("youtube.com/")){

    var vid;
    var results;

    //http://www.youtube.com/watch?v=GItD10Joaa0
    results = url.match("[\\?&]v=([^&#]*)");

    vid = ( results === null ) ? url : results[1];

    return "http://img.youtube.com/vi/"+vid+"/2.jpg";
} else if( url.match("youtu.be/") ) {

    var vid;
    var results;

    // http://youtu.be/5uxd-521uus?hd=1
    // results = url.match("[^http://youtu.be/](.*)[^?hd=1]");
    // Corrected
    results = url.match(""^http://youtu.be/(.*)(?=hd=1)");

    //alert(results[0]);
    vid = ( results === null ) ? url : results[0];

    return "http://img.youtube.com/vi/"+vid+"/2.jpg";
}
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  1. Editorial Team
    Editorial Team
    2026-05-21T11:43:59+00:00Added an answer on May 21, 2026 at 11:43 am
    "[\\?&]v=([^&#]*)"
    

    explained (after reduction from a JavaScript string to a regex):

    [\?&]   # Match a ? or a & (the backslash is unnecessary here!)
    v=      # Match the literal text "v="
    (       # Capture the following into backreference no. 1:
     [^&#]* # Zero or more characters except & or #
    )       # End of capturing group.
    

    The second regex [^http://youtu.be/](.*)[^?hd=1] is very wrong.

    It probably should read

    "^http://youtu.be/(.*)(?=hd=1)"
    
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