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Editorial Team
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Asked: 2026-06-18T06:10:36+00:00

The following code produces and undefined variable $s instead of number two define(T1,one); define(T2,two);

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The following code produces and undefined variable $s instead of “number two”

define("T1","one");
define("T2","two");

$test="number %2$s";

$test=sprintf($test, T1,T2);

echo $test;
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1 Answer

  1. Editorial Team

    Single quotes solve your problem. Double quotes cause PHP to interpolate your ‘$’ as a variable.

    <?php
define("T1","one");
define("T2","two");

$test='number %2$s';

$test=sprintf($test, T1,T2);

echo $test;

    See it working

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