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Home/ Questions/Q 3947596
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T01:16:14+00:00 2026-05-20T01:16:14+00:00

The following code return 1: Regex.Match(aaa, (a)).Groups[1].Captures.Count But I expect to receive 3: I

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The following code return 1:

Regex.Match("aaa", "(a)").Groups[1].Captures.Count

But I expect to receive 3: I see three captures of a.

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  1. Editorial Team
    Editorial Team
    2026-05-20T01:16:15+00:00Added an answer on May 20, 2026 at 1:16 am

    You need to either get the match count:

    Regex.Matches("aaa", "(a)").Count
    

    Or add a quantifier to the regex:

    Regex.Match("aaa", "(a)+").Groups[1].Captures.Count
    

    The regex (a) matches only a single a. In the first example above, that regex can be matched three times.

    In the second example the regex matches several as at once and captures each one into group 1.

    To make a choice you should consider the following differences between them:

    Regex.Matches("aaba", "(a)").Count // this is 3
    Regex.Match("aaba", "(a)+").Groups[1].Captures.Count // this is 2
    

    The second only yields two captures because it matches the first sequence of two as but then it stops matching when it finds a b. The + quantifier only matches unbroken sequences.

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