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Home/ Questions/Q 7652413
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T11:45:46+00:00 2026-05-31T11:45:46+00:00

The following code Ruby code will iterate the source string and produce a list

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The following code Ruby code will iterate the source string and produce a list of the cumulative words delimited by a ‘.’ character, other than those after the last ‘.’.

For example, give a source string of ‘Company.Dept.Group.Team’ the result will be …
[“Company.Dept.Group”, “Company.Dept”, “Company”]

Given that a while loop in Python (I believe) will test only an expression and not a statement as shown below, how would one best write this in idiomatic Python?

#ruby
source = 'Company.Dept.Group.Team'
results = []

temp = source.clone
while (i = temp.rindex('.'))  # test statement not supported in Python?
  temp = temp[0...i]
  results << temp
end

p results   # >> ["Company.Dept.Group", "Company.Dept", "Company"]
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  1. Editorial Team
    Editorial Team
    2026-05-31T11:45:47+00:00Added an answer on May 31, 2026 at 11:45 am

    The Python idiom is something like this:

    while True:
        i = temp.rindex('.')
        if not i:
            break
        ...
    
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