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Home/ Questions/Q 8099193
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T22:19:27+00:00 2026-06-05T22:19:27+00:00

The following code runs without any errors but doesn’t actually delete anything: $update =

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The following code runs without any errors but doesn’t actually delete anything:

      $update = $mysqli->prepare('DELETE FROM table WHERE RetailerID = ? AND Amount = ? AND FXRate = ?');
      $update->bind_param('iii', $rID, $base_value, $fx_rate);
      $update->execute();
      $update->close();

I have numerous mysqli prepared statments in this same file that execute fine, but this one is the only one that doesn’t modify the table. No errors or shown, but the row isn’t deleted from the table either. I have verified that $rID, $base_value, and $fx_rate are the correct values, and a row is DEFINITELY present in table that matches those values.

The only difference between this statement and the others are the parameters and the fact that it’s DELETE instead of SELECT or UPDATE. I also tried doing a SELECT or UPDATE instead of DELETE using the same WHERE parameters, but no luck. The issue seems to be that it’s not finding a row that fits the WHERE parameters, but like I said, the row is definitely there.

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-05T22:19:28+00:00Added an answer on June 5, 2026 at 10:19 pm

    Is amount an integer or a double? You’re converting to integer (‘iii’), but I presume it’ll be $0.34 or similar. Try ‘idi’ instead.

    Edit: same applies for rate – is that an integer or double too?

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