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Home/ Questions/Q 7817357
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T06:12:33+00:00 2026-06-02T06:12:33+00:00

The following code snippet causes the copy constructor to be called where I expected

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The following code snippet causes the copy constructor to be called where I expected the move constructor to be called:

#include <cstdio>

struct Foo
{
    Foo() { puts("Foo gets built!"); }
    Foo(const Foo& foo) { puts("Foo gets copied!"); }
    Foo(Foo&& foo) { puts("Foo gets moved!"); }
};

struct Bar { Foo foo; };
Bar Meow() { Bar bar; return bar; }
int main() { Bar bar(Meow()); }

On VS11 Beta, in debug mode, this prints:

Foo gets built!
Foo gets copied!
Foo gets copied!

I checked the standard and Bar seems to meet all requirements to have a default move constructor automatically generated, yet that doesn’t seem to happen unless there’s another reason why the object cannot be moved. I’ve seen a lot of move and copy constructor related questions around here but I don’t think anyone has had this specific issue.

Any pointers on what’s going on here? Is this standard behaviour?

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  1. Editorial Team
    Editorial Team
    2026-06-02T06:12:35+00:00Added an answer on June 2, 2026 at 6:12 am

    Unfortunately, VS11 doesn’t provide a default move constructor. See Move Semantics in the Remarks section – to quote:

    Unlike the default copy constructor, the compiler does not provide a
    default move constructor.

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