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Home/ Questions/Q 7612785
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:00:08+00:00 2026-05-31T02:00:08+00:00

The following code snippet: template = \ function routes(app, model){\ app.get(‘/preNew{className}’, function(req, res){\ res.render(‘{className}’.ejs,

  • 0

The following code snippet:

template = "\                                                                                
function routes(app, model){\                                                                
  app.get('/preNew{className}', function(req, res){\                                         
    res.render('{className}'.ejs, {});\                                                      
  });\                                                                                       
});".format(className=className)

throws a KeyError:

Traceback (most recent call last):   File "createController.py", line 31, in <module>
    });".format(className=className) KeyError: '  app'

Does someone know why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:00:10+00:00Added an answer on May 31, 2026 at 2:00 am

    You have a number of unescaped braces in that code. Python considers all braces to be placeholders and is trying to substitute them all. However, you have only supplied one value.

    I expect that you don’t want all your braces to be placeholders, so you should double the ones that you don’t want substituted. Such as:

    template = """                                                                  
    function routes(app, model){{
      app.get('/preNew{className}', function(req, res){{
        res.render('{className}'.ejs, {{}});                                           
      }};                                                      
    }});""".format(className=className)
    

    I also took the liberty of using triple quotes for the string literal so you don’t need the backslashes at the end of each line.

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