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Home/ Questions/Q 1063581
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:48:14+00:00 2026-05-16T18:48:14+00:00

The following code uses getchar() to accept a line of input. #include <stdio.h> #include

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The following code uses getchar() to accept a line of input.

#include <stdio.h>
#include <stdlib.h>

int main()
{
 char *rawString = (char *)malloc(200*sizeof(char));
 char *rawStringInitial = rawString;
 char c;
 c=getchar();
 while(c!='\n')
 {
  *rawString=c;
  rawString++;
  c=getchar();
 }
 *rawString='\0';
 printf("\n[%s]\n",rawStringInitial);
 return(0);
}

While typing, if I press backspace, shouldn’t it also be received by getchar() & stored in the rawString-pointed location? However the output simply shows the final string without any special characters. Could someone explain why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:48:15+00:00Added an answer on May 16, 2026 at 6:48 pm

    Standard input is (usually) buffered; non-printing characters like backspace are handled by the terminal server, and library functions like getchar() will never see them.

    If you need to read raw keystrokes, then you will need to use something outside of the C standard library.

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