Question

The following code

using System.Threading;  class Test {     volatile int counter = 0;     public void Increment()     {         Interlocked.Increment(ref counter);     } } 

Raises the following compiler warning:

'A reference to a volatile field will not be treated as volatile' 

Am I doing something wrong here to raise this warning? Why does the compiler me warn about this?

Answer 1

You are not doing anything wrong. According to the documentation:

A volatile field should not normally be passed using a ref or out parameter, since it will not be treated as volatile within the scope of the function. There are exceptions to this, such as when calling an interlocked API.