Question

The following code will call the function F from class B, but can someone please explain to me why is that. Is it possible that methods from class B overload the ones from class V (because B is inherited from V)? Thanks in advance.

#include <iostream>
using namespace std;

class V{
public: 
    void f(){ x+=2; cout << "V:"<< x;};
    int x;
};
class B: public virtual V{
public:
    void f(){ x+=3; cout << "B:"<< x;};
    int x;
};
class D: public B, virtual public V{
public:
    void g(){   x++;    f();    }
};
void main(){
    D ins;
    ins.x = 1;
    ins.g();
}

Answer 1

B::f() hides the method V::f(), this is known as function hiding.

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