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Editorial Team
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Asked: 2026-06-15T08:08:16+00:00

The following code will cause C4624 . But you can see D is not

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The following code will cause C4624. But you can see D is not the sub class of B. Why still got this warning? Thanks!

class B {
// Uncomment the following line to resolve.
// public:
~B();
};

class D  {B b;};   // C4624 B's destructor not public

More details about the warning:

C4624: ‘derived class’ : destructor could not be generated because a base class destructor is inaccessible

A destructor was not accessible in a base class and was therefore not generated for a derived class. Any attempt to create an object of this type on the stack will cause a compiler error.

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1 Answer

  1. Editorial Team

    Class members are initialised by the class’s constructor(s) and destroyed by its destructor. Their constructor(s) and destructor must therefore be accessible within those functions.

    In your example, B has a private destructor, and is therefore not accessible to the destructor of D, which needs it to destroy its member of type B.

    I’ve no idea why the error message refers to a “base class” though. If you get that error message from the code you posted, then your compiler could do with some improvements to its diagnostics.

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