Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8653945
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T14:39:52+00:00 2026-06-12T14:39:52+00:00

The following code won’t compile. Why? class A { int j; void f( int

  • 0

The following code won’t compile. Why?

class A
{
   int j;
   void f( int i = this->j );
}

Edit, for clarity. This is what I was trying to do, using less lines of code…

class A
{
   void f( int i ){};
   void f( );
   int j;
};

void A::f()
{
    f( j );
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T14:39:53+00:00Added an answer on June 12, 2026 at 2:39 pm

    Default argument values are bound at compile time.

    “this” is only defined at run time, so can’t be used.

    See here for a fuller explanation:
    Must default function parameters be constant in C++?

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following code, but it won't compile: Class<? extends something>[] classes =
Possible Duplicate: Why won't this generic java code compile? Given the following code: import
Why won't the following C code compile? It seems like it should just change
Any reason why the following code won't work? $dbconnection = db::getInstance(); //this is a
i have the following code that won't compile because of generic problems. It comes
Why won't the following code work? class parent {} class kid:parent {} List<parent> parents=new
i have the following code snippit that won't compile: procedure Frob(const Grob: WideString); var
The following code won't compile. The compiler complains about *no matching function for call
The following code won't compile on Mac OS X 10.6; it gives an error
Can anyone explain why following code won't compile? At least on g++ 4.2.4. And

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.