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Home/ Questions/Q 7970915
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T07:30:50+00:00 2026-06-04T07:30:50+00:00

The following CoffeeScript code : foo = (x) -> alert(hello) unless x? alert(world) unless

  • 0

The following CoffeeScript code:

foo = (x) ->
  alert("hello") unless x?
  alert("world") unless y?

is compiled to:

var foo;

foo = function(x) {
  if (x == null) {
    alert("hello");
  }
  if (typeof y === "undefined" || y === null) {
    return alert("world");
  }
};

Why is foo‘s argument x is not checked for undefined, while y is?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T07:30:52+00:00Added an answer on June 4, 2026 at 7:30 am

    The undefined check is to prevent the ReferenceError exception that’s thrown when you retrieve the value of a nonexistent identifier:

    >a == 1
    ReferenceError: a is not defined
    

    The compiler can see that the x identifier exists, because it’s the function argument.

    The compiler cannot tell whether the y identifier exists, and the check to see whether y exists is therefore needed.

    // y has never been declared or assigned to
    >typeof(y) == "undefined"
    true
    
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