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Home/ Questions/Q 8567759
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:57:17+00:00 2026-06-11T17:57:17+00:00

The following compiles successfully: struct Foo {} void Test() { Foo foo; foo.ToString(); }

  • 0

The following compiles successfully:

struct Foo {}

void Test()
{
    Foo foo;
    foo.ToString();
}

Whereas the following yields a “Use of unassigned local variable” compile error.

struct Foo
{
    int i;
}

void Test()
{
    Foo foo;
    foo.ToString();
}

It appears that in the first case, the compiler has made some sort of inference that since the struct has no members, they do not need to be initialized. But I’m not sure that this makes sense to me. The compiler could have forced you to initialize the foo variable as new Foo().

So, if in C# all local variables must be initialized before accessing, why does the first example compile?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:57:18+00:00Added an answer on June 11, 2026 at 5:57 pm

    Section 5.3 of the C# 5 specification covers this:

    A struct-type variable is considered definitely assigned if each of its instance variables is considered definitely assigned.

    That’s automatically the case when there are no instance variables, hence the variable is considered to be definitely assigned, and can be used in the ToString() call.

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