Question

The following contents are in a file.i use a shell script to call a python script.This python script send the mail.But in the mail contents i see the output as shown below.Its all in oneline..What am i doing wrong

 /usr/bin/python $DIR/sm.py "$message"  "`cat /tmp/alert.txt`"

Input:The following are the contents of alert.txt

  Thu Jun 28 14:29:26 IST 2012

  Disk usage limit exceeded -Current disk usage is 167G-Configured disk usage is 200HTTPD connections exceeded configured usage limit -Current HTTPD connections is 21-Configured HTTPD connection is 20


  ========================OTHER INFO==================
  Total fds: 8
  Socket fds: 0
  Other fds: 8
  Free memory :Free Memory:183732
  Buffered memory Buffered Memory:78224
  Cache memory : Cache Memory:579040
  Disk usage is 167G
  DB connections 1
  Network connections 21
  CPU Usage: 0.0

Output:

  Thu Jun 28 14:29:26 IST 2012 Disk usage limit exceeded -Current disk usage is 167G-Configured disk usage is 200HTTPD connections exceeded configured usage limit -Current HTTPD connections is 21-Configured HTTPD connection is 20 ========================OTHER INFO================== Total fds: 8 Socket fds: 0 Other fds: 8 Free memory :Free Memory:183732 Buffered memory Buffered Memory:78224 Cache memory : Cache Memory:579040 Disk usage is 167G DB connections 1 Network connections 21 CPU Usage: 0.0

This is sm.py

import logging
import smtplib
import sys
from email.MIMEText import MIMEText
from email.MIMEMultipart import MIMEMultipart


      try:
         smaid = qs[0].id
         gmailUser = '[e-mail]'
         gmailPassword = '12345'
         mailServer = smtplib.SMTP('smtp.gmail.com', 587)
         mailServer.ehlo()
         mailServer.starttls()
         mailServer.ehlo()
         mailServer.login(gmailUser, gmailPassword)

         to_addr = "[e-mail]"
         subject = sys.argv[1]
         body = sys.argv[2]
         try:
             msg = MIMEMultipart()
             msg['From'] = gmailUser
             msg['To'] = to_addr
             msg["Content-type"] = "text/html"
             sub = subject
             msg['Subject'] = sub
             body = body

             msg.attach(MIMEText(body, 'html'))
             mailServer.sendmail(gmailUser, to_addr, msg.as_string())
         except:
             write_exception("send exception")

         mailServer.close()
     except:
          write_exception("send exception1")

Answer 1

If you insist on sending HTML, you need HTML line breaks:

import cgi
# escape special HTML characters
body = cgi.escape(body)
# use HTML line breaks
body = body.replace("\r\n", "\n").replace("\n", "<br />\n")

But probably you need neither Multipart nor HTML, so you can just use smtplib.SMTP.sendmail:

headers = (('From', gmailUser), 
           ('To', to_addr), 
           ('Subject', subject))

# normalize newlines to CR+LF, as required by SMTP
body = body.replace("\r\n", "\n").replace("\n", "\r\n")

msg = '\r\n'.join("%s: %s" % kv for kv in headers) + '\r\n'*2 + body

mailServer.sendmail(gmailUser, [to_addr], msg)

Also, you should not supply the file contents via the command line, because the command line is length-restricted. Instead you should supply the file via STDIN, like in python ... < /tmp/alert.txt and read it via

import sys
body = sys.stdin.read()