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Editorial Team
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Asked: 2026-05-18T08:37:59+00:00

The following fails: $result = mysql_query(SELECT * FROM Tasks WHERE UserID = ‘$_SESSION[‘userID’]’); I

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The following fails:

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$_SESSION['userID']'");

I tried the following: 

$userID = $_SESSION['userID'];
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$userID'");

and it works. Is there a way to do this without making a separate variable?

Thanks!

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1 Answer

  1. Editorial Team

    Or like this:

    $result = mysql_query("SELECT * FROM Tasks WHERE UserID = '{$_SESSION['userID']}'");
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