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Home/ Questions/Q 8703799
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:56:49+00:00 2026-06-13T02:56:49+00:00

The following function is defined in ./kernel/sched/rt.c(v3.5.4): static void enqueue_pushable_task(struct rq *rq, struct task_struct

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The following function is defined in ./kernel/sched/rt.c(v3.5.4):

static void enqueue_pushable_task(struct rq *rq, struct task_struct *p)
{
        plist_del(&p->pushable_tasks, &rq->rt.pushable_tasks);
        plist_node_init(&p->pushable_tasks, p->prio);
        plist_add(&p->pushable_tasks, &rq->rt.pushable_tasks);

        /* Update the highest prio pushable task */
        if (p->prio < rq->rt.highest_prio.next)
                rq->rt.highest_prio.next = p->prio;
}

What I am unable to understand is that why does one want to add and delete the same node form the same list over and over. First a node is deleted from the list by plist_del and same node is added to the same list by plist_add function. Any particular reasons why this is done

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:56:50+00:00Added an answer on June 13, 2026 at 2:56 am

    When the priority of a task changes, its position in the priority list must also change.

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