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Home/ Questions/Q 764483
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T16:44:02+00:00 2026-05-14T16:44:02+00:00

The following function was suggested to me: ‘ Defines a forced casting function, which

  • 0

The following function was suggested to me:

' Defines a forced casting function, which "casts" anything that it can't detect as a number to zero.
    Function MakeInteger(val)
      If IsNumeric(val) Then
        MakeInteger = CInt(val)
      Else
        MakeInteger = 0
      End If
    End Function

Unfortunately there appear to be some things that return true for IsNumeric() but still can’t be cast as an int. Is there any better check to use?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T16:44:03+00:00Added an answer on May 14, 2026 at 4:44 pm

    See here for ‘what is wrong with isnumeric’ about this. They give this solution:

    <% 
        function isReallyNumeric(str) 
            isReallyNumeric = true 
            for i = 1 to len(str) 
                d = mid(str, i, 1) 
                if asc(d) < 48 OR asc(d) > 57 then 
                    isReallyNumeric = false 
                    exit for 
                end if 
            next 
        end function 
    
        response.write isReallyNumeric("3e4") & "<p>" 
        response.write isReallyNumeric("3d4") & "<p>" 
        response.write isReallyNumeric("&H05") & "<p>" 
        response.write isReallyNumeric("$45,327.06") & "<p>" 
        ' and a sanity check: 
        response.write isReallyNumeric("1234") & "<p>" 
    %>
    

    You’ll have to adjust if you want to
    accept certain characters as
    ‘numeric’, e.g. commas, decimal
    points, + and – signs, etc.

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