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Home/ Questions/Q 5845401
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T12:25:45+00:00 2026-05-22T12:25:45+00:00

The following is a sample string I’m using:  http://www.asfradio.com/device.asp?u=username&p=password&s=east Current checks I use in

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The following is a sample string I’m using:

 http://www.asfradio.com/device.asp?u=username&p=password&s=east

Current checks I use in my code:

if (data.endsWith(".asf") || (0 < data.indexOf(".asf")))

So in this case my check fails because yes there is a .asf string but it’s followed by radio and that makes my logic bad since this link is not asf type…

What I want is a regular expression which returns true if “.asf” is found and the next character after “f” is not a letter.

Hopefully it make sence…

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  1. Editorial Team
    Editorial Team
    2026-05-22T12:25:46+00:00Added an answer on May 22, 2026 at 12:25 pm

    In Java’s regex engine, you have the word boundary anchor \b

    Search for \\.asf\\b. In order to use that with String.matches(), you will have to wrap it with .*:

    boolean found = inStr.matches(".*\\.asf\\b.*");
    

    Better yet, store the compiled pattern in a constant:

    private static final Pattern PATTERN = Pattern.compile("\\.asf\\b");
    

    And use it like this:

    boolean found = PATTERN.matcher(inStr).find(); // not .matches()
    
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