The following is in C++.
I have a string that contains the environment variables I need to split it at the declaration of each variable & store it in a string:
char* envVars = "=::=::\0system=blah\0othervar=blah\0"
So I am using cstring functions to split the string at the occurence of the null terminator char ‘\0’ but it’s just going into an infinite loop. Why?
SOLUTION Found: look at code comments:
vector <string> GetEvironmentVariables()
{
vector <string> envVariables;
char* environVar = GetEnvironmentStrings();
char* pos = strchr( environVar, '\0' );
// As far as I know environVar =::=::\0environVar1=...\0environVar2=...\0"
// so the string has many NULL terminators
while ( pos != NULL )
{
char* buffer;
strncpy( buffer, environVar, strlen(pos) ); // on the 1st iteration: buffer SHOULD = "=::=::\0", 2nd buffer SHOULD = "environVar=...\0"
envVariables.push_back( string(buffer) );
environVar = pos; // SOLUTUION: I need to move over the '\0' pos points to so: environVar = ++pos;
pos = strchr( environVar, '\0' );
printf("Var: %s \n", envVariables.back().c_str() );
printf("env: %s \n", environVar);
system("PAUSE");
// prints out this:
// Var: cRek (same junk each iteration)
// env:
// Press any key to continue....
}
FreeEnvironmentStrings( environVar );
return envVariables;
}
I would have expected this to exit immediately, but actually the man page says:
Of course, the result of
pos = strchr(environVar, '\0');is that*pos == '\0'andstrlen(pos) == 0. So you always copy exactly zero characters. Not useful.You also set
environVar = pos;, without skipping over the NUL character. So the next call tostrchrreturnsenvironVarand no more progress is ever made.You’ve also forgotten to initialize
buffer, you’re passing a wild pointer tostrncpywhich will corrupt a random part of memory. This bug will probably rear its ugly head as soon as you fix the fact that the length parameter is always zero.