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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:16:13+00:00 2026-05-13T09:16:13+00:00

The following Java code will print 0. I would expect that this would print

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The following Java code will print “0”. I would expect that this would print “4”. According to the Java API String.split “Splits this string around matches of the given regular expression”. And from the linked regular expression documentation:

Predefined character classes
. Any character (may or may not match line terminators)

Therefore I would expect “Test” to be split on each character. I am clearly misunderstanding something.


System.out.println("Test".split(".").length); //0

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:16:13+00:00Added an answer on May 13, 2026 at 9:16 am

    You’re right: it is split on each character. However, the “split” character is not returned by this function, hence the resulting 0.

    The important part in the javadoc: “Trailing empty strings are therefore not included in the resulting array. “

    I think you want "Test".split(".", -1).length(), but this will return 5 and not 4 (there are 5 ”spaces”: one before T, one between T and e, others for e-s, s-t, and the last one after the final t.)

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