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Home/ Questions/Q 7698643
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T22:17:24+00:00 2026-05-31T22:17:24+00:00

The following java-script is working fine (Jquery) $(document).ready(function(){ $(‘#c_area’).load($(‘.m_top:first’).attr(‘href’)) }); $(‘.m_top’).click( function(){ $(#myDiv).html(‘<img src=images/loading.gif

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The following java-script is working fine (Jquery)

$(document).ready(function(){
$('#c_area').load($('.m_top:first').attr('href'))   
});
$('.m_top').click( function(){
$("#myDiv").html('<img src="images/loading.gif" alt="Wait" />');
var name= $(this).attr('href');
$('#c_area').hide().load(name).fadeIn('normal');                
$("#myDiv").html('');
return false;
});

I want to show the loading image (spinner) for 2 seconds minimum, because when page has already loaded, while click again on link, loading image (spinner) not display again because the page already loaded.

minimum time = 2 second

maximum time = until the contents loaded

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  1. Editorial Team
    Editorial Team
    2026-05-31T22:17:25+00:00Added an answer on May 31, 2026 at 10:17 pm

    Use delay(). Give the number of seconds in milliseconds like

    $('#c_area').delay(2000).hide().load(name).fadeIn('normal');   
                //^ delay for 2 sec then hide      
    

    Here is your solution.

    I used the setTimeout() to trigger the function after 2 seconds.

    $('.m_top').click( function(){          
    
        var name= $(this).attr('href');
        $('#c_area').html('<img src="images/loading.gif" alt="Wait" />');
        setTimeout( function() {
           $("#c_area").hide().load(name).fadeIn("normal");
        },2000);
    
        $("#myDiv").html('');
        return false;
    });
    
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