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Home/ Questions/Q 7181965
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T17:40:05+00:00 2026-05-28T17:40:05+00:00

The following line of code comes from the official dialog/#modal-form example allFields = $(

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The following line of code comes from the official dialog/#modal-form example

allFields = $( [] ).add( name )

Could someone please clarify what $( [] ) does? Is it the same as $("*")?

Another thing puzzled me is that I did not see allFields being added/appended to anywhere/any object, it is only created and modified. Am I missing something?

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  1. Editorial Team
    Editorial Team
    2026-05-28T17:40:07+00:00Added an answer on May 28, 2026 at 5:40 pm

    If you take a look at the doco for the jQuery() function – usually seen as the shorthand version $() – you’ll see that it accepts several different types and combinations of parameters.

    The syntax you asked about:

    $([])
    

    is the jQuery( elementArray ) syntax which lets you pass an array of DOM elements where the return will be a jQuery object wrapping those elements. By passing an empty array you basically get an empty jQuery object (just as you would if you passed a selector string that didn’t match anything, but without the inefficiency of trying to find a match first).

    When created allFields has three DOM elements added to it (where name, email and password are created just before that as jQuery objects containing one DOM element each):

    allFields = $( [] ).add( name ).add( email ).add( password )
    

    Presumably the advantage of adding the individual items rather than just doing:

    allFields = $("#name,#email,#password")
    

    is that the individual objects for each element were also needed and would’ve been created anyway, so no need to bother reselecting them via a query string.

    Another thing puzzled me is that I did not see allFields being added/appended to anywhere/any object, it is only created and modified, am I missing something?

    It is referred to in two other places in the code:

    allFields.removeClass( "ui-state-error" );
    // and, later
    allFields.val( "" ).removeClass( "ui-state-error" );
    

    This is fairly standard jQuery usage to remove a class or set the value of all elements in the jQuery object. No need for it to be added to some other object.

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