Question

The following line of code throws an Exception:

HttpResponse response = client.execute(request);    // actual HTTP request

I am able to catch it and print:

Log.e(TAG0, "Exception " + e.getMessage());

Which puts into LogCat:

03-03 14:52:11.965:
ERROR/TestHttpGet(786): Exception
http://www.google.com

Nice, but I don’t understand why the exception is thrown. All I did, prior to the line that throws the exception was:

HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet();
request.setURI(new URI("http://www.google.com/"));
HttpResponse response = client.execute(request);    // actual HTTP request

How do I progress from here?

Answer 1

1. Did you try Log.e(TAG, "Exception:", e)?
2. Is there nothing else in the TTY near the exception?
3. Do you have the INTERNET permission?