Question

The following method causes the code to break, why is this? what is unique about an NSURL that they can’t implicitly convert from NSString?

- (void)followLink
{
    [[UIApplication sharedApplication]openURL:@"http://www.google.com"];
}

Answer 1

Because you’re passing NSString to the method that expects NSURL as parameter. To fix your problem create url object from your string:

- (void)followLink
{
    [[UIApplication sharedApplication]openURL:[NSURL URLWithString:@"http://www.google.com"]];
}