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Home/ Questions/Q 8006015
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T17:22:20+00:00 2026-06-04T17:22:20+00:00

The following method generates a random string with the given length. When executed twice

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The following method generates a random string with the given length.

When executed twice in a row, the same string is given. Is anybody able to shed any light on why this might be?

 public static string GenerateRandomString(int size, bool lowerCase)
        {
            StringBuilder builder = new StringBuilder();
            Random random = new Random();
            char ch;
            for (int i = 0; i < size; i++)
            {
                ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
                builder.Append(ch);
            }
            if (lowerCase)
                return builder.ToString().ToLower();
            return builder.ToString();
        }
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  1. Editorial Team
    Editorial Team
    2026-06-04T17:22:23+00:00Added an answer on June 4, 2026 at 5:22 pm

    You are not using Random correctly.

    When calling your GenerateRandomString in a tight loop, it will end up being seeded to the same value many times.

    I suggest reading Random numbers from the C# in depth site, by Jon Skeet.

    Here is the suggested way to get a Random instance:

    using System;
    using System.Threading;
    
    
    
    public static class RandomProvider
    {    
        private static int seed = Environment.TickCount;
    
        private static ThreadLocal<Random> randomWrapper = new ThreadLocal<Random>(() =>
            new Random(Interlocked.Increment(ref seed))
        );
    
        public static Random GetThreadRandom()
        {
            return randomWrapper.Value;
        }
    }
    
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