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Home/ Questions/Q 6473975
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:31:49+00:00 2026-05-25T06:31:49+00:00

The following mockup code ends up in ConcurrentModificationException , that happens (as i understand

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The following mockup code ends up in ConcurrentModificationException, that happens (as i understand it), due to the fact that i am iterating over a set, which i am modifying.

Set<String> data = new HashSet<String>();
data.add("a=1");
data.add("b=2");
data.add("c=3");
data.add("d=4");

for (String s : data) {
    data.remove(s);
}

But why is it exactly? Please help clarify

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:31:50+00:00Added an answer on May 25, 2026 at 6:31 am

    You’re violating the iterator’s contract. From the ConcurrentModificationException javadoc,

    If a single thread issues a sequence of method invocations that
    violates the contract of an object, the object may throw this
    exception. For example, if a thread modifies a collection directly
    while it is iterating over the collection with a fail-fast iterator,
    the iterator will throw this exception.

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