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Home/ Questions/Q 8153403
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T16:00:21+00:00 2026-06-06T16:00:21+00:00

The following PHP code is working as expected. I need to echo copy error

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The following PHP code is working as expected. I need to echo “copy error” message when the code is unable to execute the command in 4 attempts.

for($num_tries = 0 ; $num_tries < 4 ; $num_tries++)
{
    $cloudcmd = "cp abc xyz ";
    system($cloudcmd,$status);
    if($status != 0)
    {
        sleep(3) ;
        continue ;
    }
    break ;
}

I tried to add echo command after break; but it does not seem to work.

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  1. Editorial Team
    Editorial Team
    2026-06-06T16:00:23+00:00Added an answer on June 6, 2026 at 4:00 pm

    Strictly, you don’t need to introduce additional variables and checks to do this.

    Keeping it simple, you can inspect the value of the for loop variable $num_tries once outside the for loop:

    if($num_tries==4)....
    

    You also have the $status variable available after the for loop.

    if($status!=0)....
    
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