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Home/ Questions/Q 9136073
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T08:54:19+00:00 2026-06-17T08:54:19+00:00

The following PHP regex removes all empty tags: #<[^\/>]*>([\s]?)*<\/[^>]*>#u I want to remove empty

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The following PHP regex removes all empty tags:

#<[^\/>]*>([\s]?)*<\/[^>]*>#u

I want to remove empty tags that do not match:

<div style="clear:both"></div>

I tried:

#^(<div style="clear:both"></div>)<[^\/>]*>([\s]?)*<\/[^>]*>#u

…but it didn’t work.

How do I add a negation?

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  1. Editorial Team
    Editorial Team
    2026-06-17T08:54:20+00:00Added an answer on June 17, 2026 at 8:54 am

    Assuming that it is well-formed and there are no missing end tags, this should do the trick:

    <(?!div\s+style=(?:"[^"]*?\bclear:\s*both\b[^"]*"|'[^']*?\bclear:\s*both\b[^']*')\s*>\s*</div>).*?>\s*</.*?>
    

    Make sure to use the case-insensitivity flag too. I would still advise against it, though.

    EDIT: I haven’t tested my edits, but I’m fairly confident that it’s a bit more thorough.

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