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Home/ Questions/Q 3488600
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Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T11:17:26+00:00 2026-05-18T11:17:26+00:00

The following program static IEnumerable<Action> Create() { foreach (var i in Enumerable.Range(0, 2)) {

  • 0

The following program

static IEnumerable<Action> Create()
{
    foreach (var i in Enumerable.Range(0, 2))
    {
        yield return () => { Console.Write(i); };
    }
}

static void Main(string[] args)
{
    foreach (var func in Create())
    {
        func();
    }

    Console.ReadLine();
}

ouputs

01

And this program

static event Action SomethingHappened;

static void Register()
{
    foreach (var i in Enumerable.Range(0, 2))
    {
        SomethingHappened += () => { Console.Write(i); };
    }
}

static void Main(string[] args)
{
    Register();
    SomethingHappened();
    Console.ReadLine();
}

outputs

11

Why is that so? How to make the program 2 output 01?

  • 1 1 Answer
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:17:27+00:00Added an answer on May 18, 2026 at 11:17 am

    You’re capturing the loop variable in your lambda expression. That means when the delegate is finally invoked, it will use the latest value of the variable… which will always be 1. Try this:

    foreach (var i in Enumerable.Range(0, 2))
    {
        int copy = i;
        SomethingHappened += () => { Console.Write(copy); };
    }
    

    … then read Eric Lippert’s blog post about it.

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