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Home/ Questions/Q 7084785
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T07:20:41+00:00 2026-05-28T07:20:41+00:00

The following program used the implementation of atomic locks from ‘Cuda By Example’, but

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The following program used the implementation of atomic locks from ‘Cuda By Example’, but running the program makes my machine frozen.
Can someone tell me what’s wrong with my program? Thanks a lot

Yifei

#include <stdio.h>


__global__ void test()
{
    __shared__ int i, mutex;

    if (threadIdx.x == 0) {
       i = 0;
       mutex = 0;
    }
    __syncthreads();

    while( atomicCAS(&mutex, 0, 1) != 0);
    i++;
    printf("thread %d: %d\n", threadIdx.x, i);
    atomicExch(&mutex,0);
}
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  1. Editorial Team
    Editorial Team
    2026-05-28T07:20:42+00:00Added an answer on May 28, 2026 at 7:20 am

    Here is a theory. I hope that you are familiar with the concept of a warp.
    In the while loop all threads within a warp will enter the while loop. Only one will exit and the rest of the threads will reside inside the while loop. This will introduce a divergent branch making the thread that exited the while loop stall until the branch converges again. Because this thread is the only one that can release the mutex this will never happen because it waits for the other threads do converge.

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