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Home/ Questions/Q 6470429
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:06:37+00:00 2026-05-25T06:06:37+00:00

The following pseudo-code is from the first chapter of an online preview version of

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The following pseudo-code is from the first chapter of an online preview version of The Algorithm Design Manual (page 7 from this PDF).

The example is of a flawed algorithm, but I still really want to understand it:

[…] A different idea might be to repeatedly connect the closest pair of
endpoints whose connection will not create a problem, such as
premature termination of the cycle. Each vertex begins as its own
single vertex chain. After merging everything together, we will end up
with a single chain containing all the points in it. Connecting the
final two endpoints gives us a cycle. At any step during the execution
of this closest-pair heuristic, we will have a set of single vertices
and vertex-disjoint chains available to merge. In pseudocode:

ClosestPair(P)
    Let n be the number of points in set P.
    For i = 1  to n − 1 do
        d = ∞
        For each pair of endpoints (s, t) from distinct vertex chains
            if dist(s, t) ≤ d then sm = s, tm = t, and d = dist(s, t)
        Connect (sm, tm) by an edge
    Connect the two endpoints by an edge

Please note that sm and tm should be sm and tm.

First of all, I don’t understand what “from distinct vertex chains” would mean. Second, i is used as a counter in the outer loop, but i itself is never actually used anywhere! Could someone smarter than me please explain what’s really going on here?

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:06:37+00:00Added an answer on May 25, 2026 at 6:06 am

    1) The description states that every vertex always belongs either to a “single-vertex chain” (i.e., it’s alone) or it belongs to one other chain; a vertex can only belong to one chain. The algorithm says at each step you select every possible pair of two vertices which are each an endpoint of the respective chain they belong to, and don’t already belong to the same chain. Sometimes they’ll be singletons; sometimes one or both will already belong to a non-trivial chain, so you’ll join two chains.

    2) You repeat the loop n times, so that you eventually select every vertex; but yes, the actual iteration count isn’t used for anything. All that matters is that you run the loop enough times.

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