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Home/ Questions/Q 6774085
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:44:42+00:00 2026-05-26T15:44:42+00:00

The following Python List Comprehension statement could be rephrased as the for loop below.

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The following Python List Comprehension statement could be rephrased as the for loop below.

>>> [(x,y) for x in range(5) if x % 2 == 0 for y in range(5) if y % 2 == 1]

>>> result = []
>>> for x in range(5):
    if x % 2 == 0:
        for y in range(5):
            if y % 2 == 1:
                result.append((x,y))

I’m having hard time understanding the following two list comprehension expressions.
What is the equivalent for loop(easier to read) way of expressing them?

[(min([row[i] for row in rows]),max([row[i] for row in rows])) 
for i in range(len(rows[0]))]

[[random.random()*(ranges[i][1]-ranges[i][0])+ranges[i][0] 
for i in range(len(rows[0]))] for j in range(k)]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:44:42+00:00Added an answer on May 26, 2026 at 3:44 pm

    Here is an example to expand the first loop , see it here : http://codepad.org/cn0UFPrD

    rows = [[1,2,3,4],[3,5,88,9],[4,55,-6,0],[0,34,22,1222]]
    t1 = [(min([row[i] for row in rows]),max([row[i] for row in rows])) for i in range(len(rows[0]))]
    print(t1)
    
    # Easy loop
    t2 = []
    for i in range(len(rows[0])):
        innerElements = []
        for row in rows:
            innerElements.append(row[i])
        newTuple = ( min(innerElements),max(innerElements) )
        t2.append(newTuple)
    
    print(t2)
    

    You can expand the second loop the same way.

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