Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8263371
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T04:04:40+00:00 2026-06-08T04:04:40+00:00

The following query does not work because the column name RowN is not valid.

  • 0

The following query does not work because the column name RowN is not valid.
Is there an elegant way to make it work properly?

select 
    *,
    ROW_NUMBER() over(PARTITION BY matricola order by esercizio desc, cod_valutazione, valutaz_sintetica, matricola, FigureOrder) AS RowN
from 
    (
select distinct
    '' as pdf,  
    Vm.NomeManager + ' ' + Vm.CognomeManager as valutatore, 
    vpd.ESERCIZIO as esercizio, 
    vpd.cod_valutazione, 
    Vm.NomeValutato +' ' + Vm.CognomeValutato as valutato,  
    vpd.matricola,  
    valutaz_sintetica,  
    vpd.COD_STATO as stato_scheda, 
    vpd.VALUTAZIONE_RANKING_SINTETICA,  
    vvv.COD_FIGURA,
    case
        when COD_FIGURA = 'OWNG' then 0
        when COD_FIGURA = 'VAL1' then 1
        when COD_FIGURA = 'OWN' then 2
    end as FigureOrder
from    
    View_SchedePerDistribuzione vpd     
    inner join RL_VALUTAZIONE_VALUTATI_VALUTATORI vvv ON vpd.COD_VALUTAZIONE = vvv.COD_VALUTAZIONE AND vpd.MATRICOLA = vvv.MATRICOLA_VALUTATO   
    inner join ValutatiManager  Vm ON vpd.MATRICOLA = Vm.MatricolaVAlutato and vpd.COD_VALUTAZIONE = Vm.COD_VALUTAZIONE 
where 
    vpd.cod_valutazione='PA_DPO_11-12' and 
    chiusa = 0 AND 
    VVV.COD_FIGURA IN ('VAL1', 'OWN', 'OWNG') AND 
    VVV.Matricola = '30000027') as tab
where 
    RowN = 1
order by esercizio desc, cod_valutazione, valutaz_sintetica, matricola, FigureOrder
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-08T04:04:41+00:00Added an answer on June 8, 2026 at 4:04 am

    Just embed it in a subquery or CTE:

    with t as (<your query minus the WEHRE and ORDER BY>)
    select *
    from t
    where RowN = 1
    order by esercizio desc, cod_valutazione, valutaz_sintetica, matricola, FigureOrder 
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

The following is what I got right now, which does not work properly because
Following query does not work in access. SELECT Fields.FieldId, PrecisionSettings.DecimalPlaces from Fields left outer
The following query does not work and it keeps giving a weird error: keys
I am wondering why the following regex does not match. string query = \1
LINQ drives me crazy. Why does following query not return the duplicates, whereas it
Why does the following query raise the error below for a row with a
Does anyone know why the following query fails in Derby? delete from MyTable where
Can anyone explain what the following PHP Code does function query($query_string) { if ($query_string
I have the following query: select mb.id as meter_id ,ds.mydate as mydate ,mb.name as
Is there a way to get the raw value of the Name property in

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.