Question

The following query is showing same user for multiple times, how to make it unique?

$query = 'SELECT   a.connection_id, a.connect_from, a.connect_to,
                   b.userid, b.thumb, c.name, d.user_id, d.field_id,
                   d.value as bday, e.creator, e.id as videoprofile,
                   DATE_FORMAT(FROM_DAYS(DATEDIFF(NOW(),d.value)), "%Y")+0 AS age
          FROM     `#__community_connection` AS a 
                   LEFT JOIN `#__community_users` AS b
                       ON a.connect_to = b.userid
                   LEFT JOIN `#__users` AS c ON a.connect_to = c.id
                   LEFT JOIN `#__community_fields_values` AS d
                       ON a.connect_to = d.user_id
                   LEFT JOIN `#__community_videos` AS e ON a.connect_to = e.creator
          WHERE    a.connect_from = "' . $uid .'" AND d.field_id = "3"
          ORDER BY DAYOFMONTH( bday ) ASC';

Answer 1

Add DISTINCT after your SELECT to return only unique rows. So change the first line of your code to the following:

$query = 'SELECT DISTINCT  a.connection_id, a.connect_from, a.connect_to, ...
[The rest of your query follows here.]